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WOE_Transformation.py
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316 lines (256 loc) · 15 KB
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import matplotlib.pyplot as plt
import pandas as pd #数据分析
import numpy as np #科学计算
from sklearn.cluster import KMeans
from sklearn.tree import DecisionTreeClassifier
from scipy import stats
plt.rcParams['font.sans-serif'] = ['SimHei']
plt.rcParams['axes.unicode_minus'] = False
def WOE_Binning(data, feature, group_num=0, method='Equval_length', cut_or_qcut=True, cut_manual=[]):
data['{}'.format(feature)] = data['{}'.format(feature)].astype(float)
if method == 'Equval_length':
group_cut = pd.cut(data['{}'.format(feature)], group_num, include_lowest=True)
if method == 'Equal_frequency':
try:
group_cut = pd.qcut(data['{}'.format(feature)], group_num)
except:
group_cut = pd.qcut(data['{}'.format(feature)], group_num, duplicates='drop', precision=3)
if method == 'Optimal': # 分箱的核心是用机器来选最优的分箱节点
r = 0
x = data['{}'.format(feature)].values
y = data['是否是诈骗电话'].values
group_max = group_num
while np.abs(r) < 1:
d1 = pd.DataFrame(
{"X": x, "Y": y, "Boundary": pd.qcut(x, group_max)}) # 注意这里是pd.qcut, Bucket:将 X 分为 n 段,n由斯皮尔曼系数决定
d2 = d1.groupby('Boundary', as_index=True)
r, p = stats.spearmanr(d2.mean().X, d2.mean().Y) # 以斯皮尔曼系数作为分箱终止条件
group_max = group_max - 1
try:
group_cut = pd.qcut(data['{}'.format(feature)], group_max)
except:
group_cut = pd.qcut(data['{}'.format(feature)], group_max, duplicates='drop', precision=3)
if method == 'Kmeans':
kmodel = KMeans(n_clusters=group_num, n_jobs=4) # 建立模型,n_jobs是并行数,一般等于CPU个数
kmodel.fit(data['{}'.format(feature)].values.reshape((len(data['{}'.format(feature)]), 1)))
# 训练模型,reshape是数组的方法
cut1 = pd.DataFrame(kmodel.cluster_centers_).sort_values(by=0) # 输出聚类中心,并且排序
cut2 = cut1.rolling(2).mean().iloc[1:] # 相邻两项求中点,作为边界点
cut3 = [0] + list(cut2[0]) + [data['{}'.format(feature)].max()] # 把首末边界点加上
group_cut = pd.cut(data['{}'.format(feature)], cut3, include_lowest=True)
if method == 'Tree':
boundary = []
x = data['{}'.format(feature)].values
y = data['是否是诈骗电话'].values
clf = DecisionTreeClassifier(criterion='gini', # “信息熵”最小化准则划分
max_leaf_nodes=group_num, # 最大叶子节点数
min_samples_leaf=0.05) # 叶子节点样本数量最小占比
clf.fit(x.reshape(-1, 1), y) # 训练决策树
n_nodes = clf.tree_.node_count
children_left = clf.tree_.children_left
children_right = clf.tree_.children_right
threshold = clf.tree_.threshold
for i in range(n_nodes):
if children_left[i] != children_right[i]: # 获得决策树节点上的划分边界值
boundary.append(threshold[i])
boundary.sort()
min_x = x.min()
max_x = x.max() + 0.10 # +0.1是为了考虑后续groupby操作时,能包含特征最大值的样本
boundary = [min_x] + boundary + [max_x]
group_cut = pd.cut(data['{}'.format(feature)], boundary, include_lowest=True)
if method == 'Other':
if cut_or_qcut:
group_cut = pd.cut(data['{}'.format(feature)], cut_manual, include_lowest=True)
else:
try:
group_cut = pd.qcut(data['{}'.format(feature)], cut_manual)
except:
group_cut = pd.qcut(data['{}'.format(feature)], cut_manual, duplicates='drop', precision=3)
return group_cut
def get_Score(woe, factor):
scores = []
for w in woe:
score = round(w * factor, 0)
scores.append(score)
return scores
def get_Table(group_cut, data,re_index = False,row_name = None):
group_cut_group = data['是否是诈骗电话'].astype(float).groupby(group_cut).count()
group_cut_group1 = data['是否是诈骗电话'].astype(float).groupby(group_cut).sum()
cardDf1 = pd.merge(pd.DataFrame(group_cut_group), pd.DataFrame(group_cut_group1), left_index=True, right_index=True)
cardDfdict = {'是否是诈骗电话_x': '总电话数', '是否是诈骗电话_y': '诈骗电话数'}
cardDf1.rename(columns=cardDfdict, inplace=True)
if re_index:
cardDf1.index = row_name
cardDf1.insert(2, 'row_name', row_name)
else:
pass
# 计算占比
cardDf1.insert(2, '诈骗电话占比', cardDf1['诈骗电话数'] / cardDf1['诈骗电话数'].sum())
cardDf1.insert(2, '分组诈骗电话占比', cardDf1['诈骗电话数'] / cardDf1['总电话数'].sum())
cardDf1.insert(2, '好电话数', cardDf1['总电话数'] - cardDf1['诈骗电话数'])
cardDf1.insert(2, '好电话占比', cardDf1['好电话数'] / cardDf1['好电话数'].sum())
# 计算WOE
cardDf1.insert(2, 'WOE', np.log(cardDf1['诈骗电话占比']) - np.log(cardDf1['好电话占比']))
# 计算IV
cardDf1.insert(2, 'IV', (cardDf1['诈骗电话占比'] - cardDf1['好电话占比']) * cardDf1['WOE'])
# 计算得分
basepoint = 600
PDO = 20
factor = PDO / np.log(2)
# offset = basepoint - PDO * np.log(PDO) / np.log(2)
cardDf1.insert(2, 'Score', get_Score(cardDf1['WOE'], factor))
return cardDf1
def get_WOE(group_cut, data):
cardDf1 = get_Table(group_cut, data)
return cardDf1['WOE']
def get_IV(group_cut, data):
cardDf1 = get_Table(group_cut, data)
IV = (cardDf1['IV']).sum()
return IV
def WOE_Transform(cut,cut_woe):
a=[]
for i in cut.unique():
a.append(i)
a.sort()
for m in range(len(a)):
cut.replace(a[m],cut_woe.values[m],inplace=True)
return cut
def WOE_Combined_Transform(group_cut,data,name,row_name = None):
cardDf1 = get_Table(group_cut, data,re_index = True,row_name=row_name)
table = pd.merge(data['{}'.format(name)], cardDf1.filter(regex='WOE|row_name'), left_on='{}'.format(name),
right_on='row_name', how='inner')
table.index = data.index
return table['WOE']
def WOE_Show(group_cut, data, feature, output='WOE',re_index = False,row_name = None):
cardDf1 = get_Table(group_cut, data,re_index = re_index,row_name = row_name)
IV = (cardDf1['IV']).sum()
#print('{}特征的IV值为:{:0.3f}'.format(feature, IV))
print(cardDf1)
if output == 'WOE':
# fig,axes=plt.subplots(2,2)
fig = plt.figure(figsize=(8, 5))
# 画WOE图
ax1 = cardDf1['WOE'].plot(linewidth=2, marker='o', title='WOE值随{}的变化趋势图,IV值为{:0.3f}'.format(feature,IV))
plt.show()
if output == 'all':
# 画分布图
ax1 = cardDf1[["好电话数", "诈骗电话数"]].plot.bar(figsize=(8, 5))
ax1.set_xticklabels(cardDf1.index, rotation=0)
ax1.set_ylabel("电话数")
ax1.set_title("{}与是否是诈骗电话分布图".format(feature))
plt.show()
# 画占比图
fig = plt.figure(figsize=(8, 5))
ax2 = cardDf1["诈骗电话占比"].plot(linewidth=2, marker='o')
ax2.set_ylabel("诈骗电话率")
ax2.set_title("诈骗电话率随{}的变化趋势图".format(feature))
plt.show()
# 画WOE图
fig = plt.figure(figsize=(8, 5))
ax1 = cardDf1['WOE'].plot(linewidth=2, marker='o', title='WOE值随{}的变化趋势图,IV值为{:0.3f}'.format(feature,IV))
plt.show()
# Equval_length,Equal_frequency,Kmeans,Optimal,Tree
# 'Other',cut_manual = [0,0.02,0.15,0.2,0.5,1]
# ['主叫次数', '平均通话时间', '被叫所属地个数', '通话失败率','工作时间通话次数', '平均呼叫离散率', '呼叫银行次数', '使用旧款手机次数', '归属地是否未知']工作非工作时间通话差值,主叫_离散率组合
# IV至少要>0.02才是有用的信息(类似于相关系数初筛);IV>0.1的要有5个以上,防止欠拟合
def WOE_main_func(data,methods,group_num,show_WOE = False,combined = False,re_index = False,row_name = None):
cut_1 = WOE_Binning(data,[column for column in data][1:][0],group_num[0],method = methods[0]) #主叫次数
cut_IV_1 = get_IV(cut_1,data)
cut_woe_1 = get_WOE(cut_1,data)
cut_2 = WOE_Binning(data,[column for column in data][1:][1],group_num[1],method = methods[1]) #平均通话时间,不单调,解释性还可以
cut_IV_2 = get_IV(cut_2,data)
cut_woe_2 = get_WOE(cut_2,data)
cut_3 = WOE_Binning(data,[column for column in data][1:][2],group_num[2],method = methods[2]) #被叫所属地个数,解释性还可以
cut_IV_3 = get_IV(cut_3,data)
cut_woe_3 = get_WOE(cut_3,data)
#cut_4 = WOE_Binning(Transdata,[column for column in Transdata][1:][3],group_num[3],method = methods[3]) #通话失败率,手动调参合并分组
cut_4 = WOE_Binning(data, [column for column in data][1:][3], group_num[3], method=methods[3],
cut_or_qcut=True, cut_manual=[0, 0.0762, 0.559, 1])
cut_IV_4 = get_IV(cut_4,data)
cut_woe_4 = get_WOE(cut_4,data)
#cut_5 = WOE_Binning(Transdata,[column for column in Transdata][1:][4],group_num[4],method = methods[4]) #平均呼叫离散率,目前可以调成2强行单调,对结果影响不大
cut_5 = WOE_Binning(data, [column for column in data][1:][4], group_num[4], method=methods[4])
cut_IV_5 = get_IV(cut_5,data)
cut_woe_5 = get_WOE(cut_5,data)
cut_6 = WOE_Binning(data,[column for column in data][1:][5],group_num[5],
method = methods[5],cut_or_qcut = True,cut_manual = [0,0.2,0.4,1]) #呼叫银行次数,这两个没救了
cut_IV_6 = get_IV(cut_6,data)
cut_woe_6 = get_WOE(cut_6,data)
cut_7 = WOE_Binning(data,[column for column in data][1:][6],group_num[6],method = methods[6]) #使用旧款手机次数,这两个没救了
cut_IV_7 = get_IV(cut_7,data)
cut_woe_7 = get_WOE(cut_7,data)
cut_8 = WOE_Binning(data,[column for column in data][1:][7],group_num[7],method = methods[7]) #归属地是否未知,目前只能分2组,Tree和Kmeans结果一样。等新数据
cut_IV_8 = get_IV(cut_8,data)
cut_woe_8 = get_WOE(cut_8,data)
cut_9 = WOE_Binning(data, [column for column in data][1:][8],group_num[8],method = methods[8]) #新增变量!!看起来还可以,工作时间通话次数
cut_IV_9 = get_IV(cut_9, data)
cut_woe_9 = get_WOE(cut_9, data)
if combined:
cut_IV_10 = get_IV([cut_1, cut_5], data)
#cut_woe_10 = get_WOE([cut_1, cut_5], Transdata)
else:
pass
if combined:
IV = pd.DataFrame(
[cut_IV_1, cut_IV_2, cut_IV_3, cut_IV_4, cut_IV_5, cut_IV_6, cut_IV_7, cut_IV_8, cut_IV_9, cut_IV_10],
index=['主叫次数', '平均通话时间', '被叫所属地个数', '通话失败率', '平均呼叫离散率',
'呼叫银行次数', '使用旧款手机次数', '归属地是否未知', '工作非工作时间通话差值', '主叫_离散率组合'], columns=['IV'])
print(IV['IV'].sort_values(ascending=False))
if show_WOE:
WOE_Show(cut_1, data, '主叫次数', 'WOE')
WOE_Show(cut_2, data, '平均通话时间', 'WOE')
WOE_Show(cut_3, data, '被叫所属地个数', 'WOE')
WOE_Show(cut_4, data, '通话失败率', 'WOE')
WOE_Show(cut_5, data, '平均呼叫离散率', 'WOE')
WOE_Show(cut_6, data, '呼叫银行次数', 'WOE')
WOE_Show(cut_7, data, '使用旧款手机次数', 'WOE')
WOE_Show(cut_8, data, '归属地是否未知', 'WOE')
WOE_Show(cut_9, data, '工作非工作时间通话差值', 'WOE')
WOE_Show([cut_1,cut_5], data, '主叫_离散率组合', 'WOE',re_index = re_index,row_name=row_name)
iv = IV['IV'].sort_values(ascending=False).plot.bar(color='b', rot=30, figsize=(10, 5), fontsize=(10))
iv.set_title('特征变量与IV值分布图', fontsize=(15))
iv.set_xlabel('特征变量', fontsize=(15))
iv.set_ylabel('IV', fontsize=(15))
plt.show()
else:
pass
else:
IV = pd.DataFrame(
[cut_IV_1, cut_IV_2, cut_IV_3, cut_IV_4, cut_IV_5, cut_IV_6, cut_IV_7, cut_IV_8, cut_IV_9],
index=['主叫次数', '平均通话时间', '被叫所属地个数', '通话失败率', '平均呼叫离散率',
'呼叫银行次数', '使用旧款手机次数', '归属地是否未知', '工作非工作时间通话差值'], columns=['IV'])
print(IV['IV'].sort_values(ascending=False))
if show_WOE:
WOE_Show(cut_1, data, '主叫次数', 'WOE')
WOE_Show(cut_2, data, '平均通话时间', 'WOE')
WOE_Show(cut_3, data, '被叫所属地个数', 'WOE')
WOE_Show(cut_4, data, '通话失败率', 'WOE')
WOE_Show(cut_5, data, '平均呼叫离散率', 'WOE')
WOE_Show(cut_6, data, '呼叫银行次数', 'WOE')
WOE_Show(cut_7, data, '使用旧款手机次数', 'WOE')
WOE_Show(cut_8, data, '归属地是否未知', 'WOE')
WOE_Show(cut_9, data, '工作非工作时间通话差值', 'WOE')
iv = IV['IV'].sort_values(ascending=False).plot.bar(color='b', rot=30, figsize=(10, 5), fontsize=(10))
iv.set_title('特征变量与IV值分布图', fontsize=(15))
iv.set_xlabel('特征变量', fontsize=(15))
iv.set_ylabel('IV', fontsize=(15))
plt.show()
else:
pass
Transdata_woe=pd.DataFrame() #新建df_new存放woe转换后的数据
Transdata_woe['是否是诈骗电话']=data["是否是诈骗电话"]
Transdata_woe['主叫次数']=WOE_Transform(cut_1,cut_woe_1)
Transdata_woe['平均通话时间']=WOE_Transform(cut_2,cut_woe_2)
Transdata_woe['被叫所属地个数']=WOE_Transform(cut_3,cut_woe_3)
Transdata_woe['通话失败率']=WOE_Transform(cut_4,cut_woe_4)
Transdata_woe['平均呼叫离散率']=WOE_Transform(cut_5,cut_woe_5)
Transdata_woe['呼叫银行次数']=WOE_Transform(cut_6,cut_woe_6)
Transdata_woe['使用旧款手机次数']=WOE_Transform(cut_7,cut_woe_7)
Transdata_woe['归属地是否未知']=WOE_Transform(cut_8,cut_woe_8)
Transdata_woe['工作非工作时间通话差值'] = WOE_Transform(cut_9,cut_woe_9)
if combined:
Transdata_woe['主叫_离散率组合'] = WOE_Combined_Transform([cut_1, cut_5],data,'主叫_离散率组合',row_name = row_name)
else:
pass
#Transdata_woe.to_csv('WoeData.csv', index=False)
return Transdata_woe