Make std::initializer_list visible.#9
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andreasfertig merged 1 commit intomasterfrom May 21, 2018
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With C++11 uniform initialization and initializer lists we cannot
longer easily see whether we are calling a normal constructor or one
which takes a initializer_list. For example:
struct V {
V(int x) {}
V(std::initializer_list<int> x) {}
};
V v{1};
V vv{1, 2};
Surprisingly to some people, in both cases the second constructor, taking
a std::initializer_list, is used.
This change shows the difference by putting the name
std::initializer_list<T> in front of an initializer list.
Codecov Report
@@ Coverage Diff @@
## master #9 +/- ##
==========================================
+ Coverage 95.36% 95.44% +0.08%
==========================================
Files 40 42 +2
Lines 1595 1623 +28
==========================================
+ Hits 1521 1549 +28
Misses 74 74
Continue to review full report at Codecov.
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With C++11 uniform initialization and initializer lists we cannot
longer easily see whether we are calling a normal constructor or one
which takes a initializer_list. For example:
struct V {
V(int x) {}
V(std::initializer_list x) {}
};
V v{1};
V vv{1, 2};
Surprisingly to some people, in both cases the second constructor, taking
a std::initializer_list, is used.
This change shows the difference by putting the name
std::initializer_list in front of an initializer list.